What mass of sodium is needed to produce 108.2g of sodium oxide (Na20)?- Should be easy for you clever clogs!?

Yeah, its in the question, i'm stuck on how i'd go about answering it, any1 want to have a go?





Thanks in advance :)

What mass of sodium is needed to produce 108.2g of sodium oxide (Na20)?- Should be easy for you clever clogs!?
4Na + 02 ====%26gt; 2Na2O





92g of Sodium produces 124g of Sodium Oxide.


xg of Sodium produces 108.2g of Sodium Oxide.





92/x = 124/108.2


x = 92*108.2/124


x = 80.3





80.3 grams of Sodium is needed.
Reply:63.80g
Reply:The reaction is :





4 Na + O2 ---%26gt; 2 Na2O





The first thing to do is the calculate the number of mol 108.2 g of Na2O is:





MW of Na2O = 2*23 + 16 = 62 g/mol


mol of Na2O = 108.2/62 = 1.745 mol of Na2O present.





Now looking at the reaction there needs to be twice as much sodium metal present than the amount of Na2O produced, so:





1.745*2 = mol of Na needed = 3.49 mol





now convert this amount of Na into the number of grams by multiplying by the molecular weight of Na





3.49 mol * 23 g/mol = 80.27 g of Na needed for this reaction.



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